Hacker Rank Problem
Input Format
You will be given two positive integers, and (), separated by a newline.
Output Format
For each integer in the interval :
- If , then print the English representation of it in lowercase. That is "one" for , "two" for , and so on.
- Else if and it is an even number, then print "even".
- Else if and it is an odd number, then print "odd".
Note:
Sample Input
8
11
Sample Output
eight
nine
even
odd
Hacker Rank Problem Solution
#include <iostream> #include <cstdio> using namespace std; // Sumit Kumar int main() { string str[] = {"","one","two","three","four","five","six","seven","eight","nine"}; int a,b; cin >> a >> b; for(int i = a; i <= b; i++){ if(i <= 9)cout << str[i] << endl; else{ if(!(i%2))cout << "even" << endl; else cout << "odd" << endl; } } return 0; } |
}
only three test cases are pass bro
ReplyDeleteint main()
ReplyDelete{
string str[] = { "","one","two","three","four","five","six","seven","eight","nine" };
int a, b;
cin>>a >> b;
for (int i = a; i <= b; i++) {
if (1 >= i || i <= 9) {
cout< 9) {
if (i % 2 == 0) {
printf("even\n");
}
else {
cout << "odd\n";
}
}
}
return 0;
}